Boats and Streams - Concepts and Tricks - Part 2

thank u sir.
these viedoes are very helpful to me.

Good work... Thank you..!! :) :)

simly its awasome teaching

First of all thanks for the concept clarification... Dont mind but if only you could give examples besides the ones (and that too from the 1st page itself) from rs aggarwal

hey how did u derive the formulae 1/2(a-b) and 1/2(a+b)

ur videos are very help full but i couldnt understand the last problen

very nice explanation.. good going... we appreciate ur efforts & worth watching ur videos.. keep it up.. carry on...

Hi Dani, I like your way of narration and the presentation as a whole..thumbs up!

last problem not understood

last problem not understood

Great work man😁😁👍🏼👍🏼

Superb problem 2 explian mircleeee sir.... i need many videos on si@ci plg uplode

this video was very helpful. Finally got my boats and steam concept cleared which I kept pending probably for a very long time

thank you so much denial..!!

Really helpful bro .....m doing preparation for MBA ... very hardly I get time to do study ... but your video helping me more to rewis .... thanks

Please upload more chapters from Quantitative Aptitude section ...finding ur way of explaining more helpful in understanding the concepts ....Thanks.....

Your each and every Lectures are awesome . But just a suggestion that in competitive exams we need to solve it much faster , as in problem 3 it is given that
upstream is thrice downstream.
So Downstream= 3(Upstream) .. Replacing the formula given by you
(u+v)=3(u-v) implies u+v = 3u-3v .
SO we have equation
2v=u (where v is rate of stream and u=18kmph as Given in Question) .
v=18/2 that is 9 kmph . :) . I hope You dont mind. It was a just a suggetion.

ooo!! I think the last problem can be solved in much quicker way...and hope most of us will agree with me...

If you first calculate the speed of the current for 6 hrs.,which is just (32-14)=18,then find it for an hr.,which is (18/6)=3kmph & finally (3/2)=1.5kmph.I think this is faster approach,not sure for others..

Good teaching. But do you have any short cut to solve this kind of problem?. i think its bit lengthy. But if v practice on this then can solve fast.